Last updated on July 17th, 2025
We use the derivative of 8^x, which is 8^x ln(8), as a tool to understand how the exponential function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now discuss the derivative of 8^x in detail.
We now understand the derivative of 8^x. It is commonly represented as d/dx (8^x) or (8^x)', and its value is 8^x ln(8). The function 8^x has a clearly defined derivative, indicating it is differentiable across its domain.
The key concepts are mentioned below:
Exponential Function: (8^x is an exponential function).
Derivative Rule for Exponential Functions: Rule for differentiating a^x, where a is a constant.
Natural Logarithm: ln(8) is used in the differentiation process.
The derivative of 8^x can be denoted as d/dx (8^x) or (8^x)'.
The formula we use to differentiate 8^x is: d/dx (8^x) = 8^x ln(8) (or) (8^x)' = 8^x ln(8)
The formula applies to all x in the domain of real numbers.
We can derive the derivative of 8^x using proofs. To show this, we will use the properties of exponential functions along with the rules of differentiation. There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of 8^x results in 8^x ln(8) using the above-mentioned methods:
By First Principle The derivative of 8^x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of 8^x using the first principle, we will consider f(x) = 8^x. Its derivative can be expressed as the following limit.
f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)
Given that f(x) = 8^x, we write f(x + h) = 8^(x + h).
Substituting these into equation (1), f'(x) = limₕ→₀ [8^(x + h) - 8^x] / h = limₕ→₀ [8^x * 8^h - 8^x] / h = 8^x * limₕ→₀ [8^h - 1] / h
Using the limit property, we have limₕ→₀ [8^h - 1] / h = ln(8) Thus, f'(x) = 8^x * ln(8)
Hence, proved.
Using Chain Rule To prove the differentiation of 8^x using the chain rule, Consider y = 8^x = e^(x ln(8)) Let u = x ln(8), then y = e^u
Applying the chain rule: dy/dx = dy/du * du/dx dy/du = e^u = e^(x ln(8)) = 8^x du/dx = ln(8)
Therefore, dy/dx = 8^x * ln(8)
Using Exponential Rule We use the standard rule for differentiating exponential functions:
If y = a^x, then dy/dx = a^x ln(a) Applying this to y = 8^x, we get: dy/dx = 8^x ln(8)
This shows the derivative of 8^x is 8^x ln(8).
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like 8^x.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, denoted using f′′ (x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth derivative of 8^x, we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
The exponential function 8^x is defined for all real numbers, so there are no undefined points. When x = 0, the derivative of 8^x = 8^0 ln(8) = ln(8).
Students frequently make mistakes when differentiating 8^x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (8^x * ln(x)).
Here, we have f(x) = 8^x * ln(x). Using the product rule, f'(x) = u′v + uv′ In the given equation, u = 8^x and v = ln(x).
Let’s differentiate each term, u′ = d/dx (8^x) = 8^x ln(8) v′ = d/dx (ln(x)) = 1/x
Substituting into the product rule, f'(x) = (8^x ln(8)) * ln(x) + 8^x * (1/x)
Let’s simplify terms to get the final answer, f'(x) = 8^x ln(8) ln(x) + 8^x / x
Thus, the derivative of the specified function is 8^x ln(8) ln(x) + 8^x / x.
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A company is modeling its growth using the function y = 8^x, where y represents revenue in millions, and x is the number of years. Find the rate of change of revenue when x = 3 years.
Given y = 8^x, the rate of change of revenue is the derivative of y with respect to x. dy/dx = 8^x ln(8).
Substitute x = 3 into the derivative: dy/dx = 8^3 ln(8) dy/dx = 512 ln(8)
Hence, the rate of change of revenue when x = 3 years is 512 ln(8) million dollars per year.
We calculate the rate of change of revenue by finding the derivative of the function y = 8^x and substituting x = 3 into the derivative. This gives us the rate at which revenue is increasing at that point in time.
Derive the second derivative of the function y = 8^x.
The first step is to find the first derivative, dy/dx = 8^x ln(8)...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [8^x ln(8)] = ln(8) * d/dx [8^x] = ln(8) * (8^x ln(8)) = ln(8)² * 8^x
Therefore, the second derivative of the function y = 8^x is ln(8)² * 8^x.
We use the step-by-step process, where we start with the first derivative. We then differentiate it again to find the second derivative, ensuring each step follows the exponential rule.
Prove: d/dx (8^(2x)) = 2 * 8^(2x) ln(8).
Let’s start using the chain rule: Consider y = 8^(2x) = (8^x)²
To differentiate, we use the chain rule: dy/dx = 2 * (8^x) * d/dx [8^x]
Since the derivative of 8^x is 8^x ln(8), dy/dx = 2 * 8^x * 8^x ln(8) = 2 * 8^(2x) ln(8)
Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. We replace 8^x with its derivative, and as a final step, simplify the expression to show the desired result.
Solve: d/dx (8^x / x).
To differentiate the function, we use the quotient rule: d/dx (8^x / x) = (d/dx (8^x) * x - 8^x * d/dx(x)) / x²
We will substitute d/dx (8^x) = 8^x ln(8) and d/dx (x) = 1 = (8^x ln(8) * x - 8^x * 1) / x² = (x * 8^x ln(8) - 8^x) / x²
Therefore, d/dx (8^x / x) = (x * 8^x ln(8) - 8^x) / x².
In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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